how to create an action to run a batch file?
##Start Process
Action …
Another way is JScript file.X()
helper …
##file.X
##
string file.ReadFromFile(string fileName)
void file.WriteToFile(string fileName, string content)
void file.AppendToFile(string fileName, string content)
file.Starter(<filePath>).Execute();
file.Starter(<filePath>).Hidden.Execute();
file.Starter(<filePath>).With(<arguments>).Execute();
file.Starter(<filePath>).WorkOn(<workingDir>).Execute();
Instead of using .Execute()
you can use .ShellExecute()
.
file.For('c:\\folder\\test.txt').Starter().Execute();
file.For('c:\\folder\\test.txt').CreateFolder().Write('test 123');
file.For('c:\\folder\\test.txt').CreateFolder().Append('test 123');
file.For('c:\\folder\\test.txt').CreateFolder().Read();
file.For('c:\\folder\\test.txt').Delete();
Example:
function batt() {
var batFile = "D:\\Programs\\POS\\battery.bat";
var r = file.For(batFile).Starter().Hidden.ShellExecute();
return r;
}
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wow thanks a lot. i am trying to directly send the receipt printing saved in C: user \ Sambapos5 \ Received.
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